Given the equation square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution.

a)x = one fourth, solution is not extraneous
b)x = one fourth, solution is extraneous
c)x = 3, solution is not extraneous
d)x = 3, solution is extraneous

An extraneous solution is a root that when substituted to the original equation, the answer becomes invalid. In this respect, the equation is square root (8x + 1) = 5; 8x + 1 = 25; x1 = 3;  8x + 1 = -25 ; x2 = -26/8 = -13 /4. Upon substitution, square root of (8*3 + 1 ) = 5, this is valid. Hence the answer to this question is C.