Luiza is jumping on a trampoline. H(t)H(t)

H(t)

H, left parenthesis, t, right parenthesis

models her distance above the ground (in

m\text{m}

m

start text, m, end text

)

tt

t

t

seconds after she starts jumping. Here,

tt

t

t

is entered in radians.

H(t)=−0.6cos⁡(2π2.5t)+1.5H(t) = -0.6\cos\left(\dfrac{2\pi}{2.5}t\ri ght) + 1.5

H(t)=−0.6cos(

2.5

2π



t)+1.5

H, left parenthesis, t, right parenthesis, equals, minus, 0, point, 6, cosine, left parenthesis, start fraction, 2, pi, divided by, 2, point, 5, end fraction, t, right parenthesis, plus, 1, point, 5

What is the second time when Luiza reaches a height of

1.2 m1.2\text{ m}

1.2 m

1, point, 2, start text, space, m, end text

?

Round your final answer to the nearest hundredth of a second.

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

i saw this question before, dont know the asnwer srry

step-by-step explanation:

8.75

how-to:

first, we need to find what we have to work with.

since i know that we have 7 (years) and 0.8 (inches), we can use these to solve and find the equation!

secondly, what you want to do, is see that we need to know how much growth out of the 0.8 inches he got in only 1 year, instead of 7 years.

let's try to divide.

7 ÷ 0.8 = 8.75