Find the equation of a circle that has its center at (6,-4) and has a radius of 3.

( x-6) ^2 + ( y+4) ^2 = 9

Step-by-step explanation:

The equation of a circle is given by

( x-h) ^2 + ( y-k) ^2 = r^2  where (h,k) is the center and r is the radius

( x-6) ^2 + ( y- -4) ^2 = 3^2

( x-6) ^2 + ( y+4) ^2 = 3^2

( x-6) ^2 + ( y+4) ^2 = 9

i can't solve unless i know what the line is

step-by-step explanation:

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step-by-step explanation:

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