What is the area of the irregular polygon shown below? 18
F
3.5
18
O A. 60 sq. units
B. 86 sq. units
C. 79 sq. units
D. 100 sq. units

Option B: 49 square units.

Step-by-step explanation:

The irregular polygon consists of a rhombus a square.

Area of rhombus = 0.5*(product of diagonals).

Area of square = length * length = l^2.

The diagonals of the rhombus measure 8 units and 6 units respectively. The diagram shows the length of half of the diagonals, so doubling both the lengths gives us the required lengths. The side of the square measures 5 units. Substituting all the information in the formula:

Total Area = Area of rhombus + Area of square.

Total Area = 0.5*8*6 + 5^2.

Total Area = 24 + 25

Total Area = 49 square units.

Option B is correct! Hope this helps! :)

idk

step-by-step explanation:

use that smart brain

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.