For f(x) = 2x + 1 and g(x) = x^2- 7, find (f - g)(x). ?

(f-g)(x)=-x^(2)+2x+8

the solutions are:

x=4 or x=-2

Step-by-step explanation:

(f-g)(x)=2x+1-(x^(2)-7)

(f-g)(x)=-x^(2)+2x+1+7

(f-g)(x)=-x^(2)+2x+8

does this help or should I solve for the zeros/solutions of this quadratic equation?

then:

-x^(2)+2x+8=0

-(x^(2)-2x-8)=0

x^(2)-2x-8=0

(x-4)(x+2)=0

x=4 or x=-2

a negative exponent is translated as follows:

so, we have