A normal distribution has a mean of 10 and a standard deviation of 1. What is the probability of selecting a
number that is at most 9?

15.87% probability of selecting a number that is at most 9

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

What is the probability of selecting a number that is at most 9?

This is the pvalue of Z when X = 9. So

has a pvalue of 0.1587

15.87% probability of selecting a number that is at most 9

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3