The management of Acme Manufacturing Company is considering the introduction of a new product. The fixed cost to begin the production of the product is $100,000. The variable cost for the product is uniformly distributed between $20 and $28 per unit. Demand for the product is best described by a normal probability distribution with a mean of 5000 units and a standard deviation of 1250 units. (a) Perform a simulation of 500 trials. (b) What are the mean variable cost/unit and mean demand from the simulation? (c) What are the mean and standard deviation of the profit from the simulation? (d) Create a histogram showing the profit distribution. (e) What is the probability the product will result in a loss? (f) What is the value at risk (at 5%)? (g) Suppose Acme wants to introduce the product only if probability of loss is no more than 10%. Based on this, what is your recommendation?

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2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

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there are infinitely many solutions.