Q1.work out the sum of the interior angles of a pentagon. Q2.work out the size of one interior angle of a regular octagon.
Q3.work out the size of one exterior angle of a regular hexagon

Question 1:

The sum of interior angles of a polygon can be found by the following formula:

(n-2) × 180

Where n is the no. of sides

A pentagon has 5 sides

So,

= (5-2) × 180

= (3) × 180

= 540 degrees

Question 2:

Since The sum of interior angles of a regular octagon is 1080 and the total interior angle are 8

So, Measure of interior angle =

Measure of interior angle = 135 degrees

Question 3:

Since, one interior angle in a hexagon measures 120 degrees.

So,

The interior angle should be subtracted by 180 to get the exterior angle.

Exterior angle = 180-120

Exterior Angle = 60 degrees

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°

it would rotate about 180 degrees.