Find n so that (4/5)^3 × (4/5)^-6 = (4/5)^2n-1

the answer is stop cheating on things stoopid

step-by-step explanation:

im eatin up the 44

c

step-by-step explanation: easy math

      2

  2 is to go somewhat to the top right of a because it is squared    

v= a h/3

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.