Triangle ABC, with the vertices at A(0,0) B(3,5) and C(0,5) is graphed on the set of axes shown below. Name the solid that is formed when triangle ABC is rotated continuously about side AC and state the radius of the solid

Solid formed will be a CONE

Radius of the cone = 3 units

Step-by-step explanation:

Given points of a triangle are A(0, 0), B(3, 5) and C(0, 5).

Given triangle is a right triangle.

When the given triangle ABC is rotated about a line AC, a 3D image of a solid will be created in the form of a CONE.

This cone will have the radius = BC

Length of side BC =

                              =

                              = 3

Therefore, radius of the cone = 3 units

angle q= 92 degree

step-by-step explanation:

the solution is in the picture

when a quadrilateral is inscribed in a circle, the opposite angles are supplement to each other. in other words, the sum of the 2 angle is 180 degree

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form