A = (5,2), B = (2,4), C = (6,7) and D = (9,5) What is the length of the shorter diagonal of parallelogram ABCD?

Step-by-step explanation:

The diagonals are AC and BD.

Now we find the lengths of the diagonals using the distance formula.

AC:

BD:

Since sqrt(26) < sqrt(50), then the shorter diagonal is AC.

AC = sqrt(26) or approximately 5.1

A = (5.2)

Step-by-step explanation:

c2= (6-5)^2 + (7-2)^2

To find AC we calculate within parenthesis (6-5) : 1

c2= 1 + (7-2)^2

calculate within parenthesis (7-2) : 5

c2 = 1^2 + 5^2

then calculate exponents 1^2:1

c^2 = 1+5^2

add and subtract left to right

c^2 = 1+25

c^2 =26

Sr of 26 = 5.09901951359

Which means the closest answer is A = 5.2

To find BD we calculate within parenthesis (9-2):7

c2= (9-2)^2 + (5 - 4)^2

calculate within parenthesis (5-4) : 1

c2 = (7)^2 + (1)^2

calculate exponents 1 ^2 : 1

c2 = 49 +1

add and subtract left to right

c2 = 50

Sr of 50 = 7.07106781187

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step-by-step explanation: