Find the equation of the line passing through the point (–1, 5) and perpendicular to the line y = – 3x + 4. answers : A) 3y = x + 16 B) 3y = –x + 16 C) y = –3x + 2 D) y = –3x + 8

3y=x+16

Step-by-step explanation:

If you plot the gradient must be 1/3 since its perpendicular. Only the option has the gradient as 1/3.

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?