![(\sqrt[3]{8})^{\frac{1}{4}x}=(8^{\frac{1}{3}})^{\frac{1}{4}x}\\\\=8^{\frac{1}{3}*\frac{1}{4}x}\\\\=8^{\frac{1}{12}x}\\\\=\sqrt[12]{8}^{x}](/tpl/images/0692/1757/801b0.png)
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Mathematics, 23.06.2020 10:57 dianactorres
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