Plz help. I’m trying but I can’t. Figure this one out. Mainly because the equations aren’t lined up accordingly with the variables

x = 2

y = 1

z = 3

Step-by-step explanation:

Okay, we know y=z-x.

Let's plug in that y-value into the first equation: x + 2 (z - x) -z =1

Simplify that down to x +2z -2x -z = 1

Equation 1 becomes -x + z = 1

Let's plug it into equation 3 and solve to get: 2x - (z - x) +3z = 12

Equation 3 becomes 3x + 2z = 12

Now let's use system of equations for those two equations we just found

3x + 2z = 12

-2x + 2z = 2 > multiplied this by 2 to simplify

subtract, and you 5x = 10, x = 2

Use x = 2 and solve for the other variables using the same method (try this on your own!) to get y = 1 and z = 3

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584