Suppose a baby food company has determined that its total revenue R for its food is given by R = − x 3 + 33 x 2 + 720 x where R is measured in dollars and x is the number of units (in thousands) produced. What production level will yield a maximum revenue?

A production level of 30 thousand units (x = 30)

Step-by-step explanation:

To find the production level (value of x) that will yield the maximum revenue, we can take the derivative of the function R in relation to x and find when it is equal to 0:

dR/dx = -3x2 + 66x + 720 = 0

x2 - 22x - 240 = 0

Solving the quadratic equation using Bhaskara's formula, we have:

Delta = (-22)^2 + 4*240 = 1444

sqrt(Delta) = 38

x1 = (22 + 38)/2 = 30

x2 = (22 - 38)/2 = -8

The negative value is not valid for our problem, so we have that the value that gives the maximum revenue is x = 30

abde or 1,2,4, 5 is the answer

step-by-step explanation:

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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