Find the 11th term from the end of the A. P 10,7,4 -62.

-32

Step-by-step explanation:

a=10, d = 7-10 = -3

First find which term is -62

an = -62

a = (n-1) d= -62

Putting values

10 + (n-1)(-3) = -62

10 + (n(-3) -1 (-3) = -62

10 - 3n + 3 = -62

13 - 3n = -62

-3n = -62-13

n = 75/3 = 25

We need to find out 11th term from the last term ie., 25 - 10 = 15th term

So we need to find a14

an = a +(n-1) d

a15 = 10+ (15-1) (-3)

= 10 + 14 (-3)

= 10 -42

= -32

So the 11th term from the 15th term from the first = -32

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.