A mannequin is dropped from the top of a fire department training tower onto a rescue trampoline 67 feet below. How long does it take before the mannequin is caught by the trampoline? Use h(t) = -16t2 + 67.

I got 2.09375 seconds using differential calc, but -2.046 using the quadratic formula

Step-by-step explanation:

Im unsure which technique is supposed to be used her. I didnt know if this was a calculus problem or a quadratic equation. So, choose from the two answers depending on which class this is for

Differential:

h(t) is the height with respect to time. So I changed it to h'(t) and took the derivative of the function using the power rule.

Quadratic:

There is no B here so the formula boils down to the square root of -4ac/2a

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v