Please help , factor 6x^2-33x+15 A. 3(2x-5)(x+1) B. 3(x+1)(2x+5) C. 3(2x-1)(x+5) D. 3(x-5)(2x-1)

D

Step-by-step explanation:

Since the end term is positive, we know the 1 and 5 must both be positive or negative. However since -33x is negative, we know 1 and 5 are both negative too

3(2x-1     )(x-5   )  

Step-by-step explanation:

6x^2-33x+15

Factor out the greatest common factor

3(2x^2 -11x +5)

Factor inside the parentheses

3(2x     )(x   )  

We need to get to -11 so the the only factors of 5 are 1 and 5 and they have to be negative

3(2x-1     )(x-5   )  

2 * -5 + -1 = -10-1 = -11

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°