one x-intercept for a parabola is at the point (1,0). use the factor method to find the other x-intercept for the parabola defined by y=2x^2+2x-4

(- 2, 0 )

Step-by-step explanation:

Given

y = 2x² + 2x - 4

To find the x- intercepts let y = 0, that is

2x² + 2x - 4 = 0 ( divide through by 2 )

x² + x - 2 = 0 ← in standard form

(x + 2)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 1 = 0 ⇒ x = 1

x- intercepts are x = - 2, x = 1, that is

(1, 0 ) and (- 2, 0 )

The other x- intercept is (- 2, 0 )

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!

idk wbu

step-by-step explanation: