The shaded prism below is created from the rectangular box as shown. Points A, B, and C are midpoints of their respective edges. Explain, using Cavalieri's Principle, why the volume of the shaded prism must be one-fourth of the volume of the original rectangular box. I promise to give you brainliest. please it's urgent. help me.

The volume of the prism is 1/4 of the volume of the rectangular box.

Step-by-step explanation:

The figure alluding to the exercise is required, according to the description I will attach the one that must be to be able to solve the exercise.

The first thing is that the cross sections of the prism are triangles and in addition those triangles are congruent to each other with areas equal to the area of the base triangle.

By congruence we can say that the triangle has 1/4 of the area of the base rectangle. We can affirm that the height of the prism is equal to the height of the rectangular box.

Now, the Cavalieri principle states that if two solids have the same height and their cross-sectional areas taken parallel and at equal distances from their bases are always equal, then they have the same volume.

now in this case the cross-sectional areas (parallel to the base) of the prism and the cross-sectional areas (parallel to the base) of the cuboid with a height equal to that of the rectangular box and the length, width of half of the sizes of the rectangular box are always the same.

Which means that the volume of the parallelepiped is 1/4 the volume of the rectangular box and thanks to this we can say that the volume of the prism is 1/4 of the volume of the rectangular box.

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.