write the equation of the line that passes through the points (-1, 2) and (6,3) in slope-intercept form

Step-by-step explanation:

first, lets find the slope:

m=(y2-y1)/(x2-x1)

m=(3-2)/(6-(-1))

m=1/7

y=(1/7)*x+b

to find b lets pug in a point we know into the equation:

3=(1/7)*6+b

21/7=6/7+b

b=(21/7)-(6/7)

b=15/7

now we know the equation in slope intercept form representing this function is:

y=(1/7)*x+(15/7)

y= 1/7x+15/7

Step-by-step explanation:

points

(-1, 2)  and  (6, 3)

slope intercept form:

2= -m+b, 3= 6m+b ⇒ m= 1/7 ⇒ b= 2 1/7= 15/7

1. 8

2. 9

3. 20

4. 3

5. 17

6. 2.2

7. 11.25

8. 1

9. 14

10. 2

step-by-step explanation:

thats the first half

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.