PLI HELP ME ASAP!
Lisa chooses x boys and y girls to join a Mathematics Competition. The total number of pupils chosen is not more than 24 and the number of girls exceeding the number of boys at least by 4

a) Write two linear inequalities
b) Calculate the minimum and maximum number of girls if Lisa chooses 8 boys

Step-by-step explanation:

a)

total no. of pupils is not more than 24

therefore first equation is

(x+y) ≤ 24. (1)

No. of girls exceeding the no. of boys by atleast 4

(y-x) ≥ 4. (2)

b) Now Liza chooses 8 boys

Maximum no. of girls = ?

Using first inequality

y+8= 24 ( maximum value of less than or equal to function is equal to itself)

Therefore,

y= 24-8

=16

Minimum no. of girls = ?

Using second inequality

y-8 =4 (minimum value of greater than or equal to function is equal to itself)

Therefore,

y= 4+8

y=12

a) 2linear inequalities

(x+y) ≤ 24

(y-x) ≥ 4

b) Max no. of girls = 16

Min no. of girls = 12

Hope it helps...

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!