Find the perimeter of the triangle defined by the coordinates (9,0) , (-5,0) and (-10,6)

PERIMETER = 41.73 units

Step-by-step explanation:

To find the perimeter of the triangle, we will follow the  steps below:

Let the coordinate of the triangle be ABC, that is

A(9,0)    B(-5,0)   and   C(-10,6)

We will first find distance AB, BC  and CA using the distance formula

|D| = √(x₂-x₁)² +(y₂-y₁)²

A(9,0)    B(-5,0)

x₁ =9  y₁=0    x₂=-5    y₂=0

substitute the values into the formula

|AB| = √(-5-9)² +(0-0)²

       = √(-14)² +(0)²

       =√196

        =14

|AB| = 14 units

B(-5,0)      C(-10,6)

x₁ =-5  y₁=0    x₂=-10    y₂=6

substitute the values into the formula

|BC| = √(-10+ 5)² +(6-0)²

         =√(-5)² +(6)²

         =√25 + 36

         =√61

         ≈7.81

|BC| ≈7.81 units

C(-10,6)     A(9,0)

x₁ =-10  y₁=6   x₂=9  y₂=0

substitute the values into the formula

|CA| = √(9+10)² +(0-6)²

         = √(19)² +(-6)²

         =√361 +36

        =√397

        ≈19.92 units

|CA|≈19.92 units

Perimeter of triangle = |AB|+|BC|+|CA|

                                  =14+7.81+19.92

                                  =41.73

PERIMETER = 41.73 units