One of the two numbers is 2 less than twice the other number. If the product of these numbers equals to 40, find the numbers. Only algebraic

solutions will be accepted.

hey

let s note a and b the two numbers

we can write

(1) a = 2b - 2

(2) ab = 40

from (2) we can say for b different from 0 that

a = 40/b

replace it in (1)

40/b=2b-2

so

2(b-1)b = 40

b(b-1) = 20

5 is a trivial solution and as the product of the two solutions is -20 then the second solution is -4 therefore

<=> (b-5)(b+4) = 0

<=> b = 5 or b = -4

so we have

a= 40/b = 8 and b = 5

or

a = 40/b = -10 and b = -4

(8,5) and (-10.-4) are solutions

do not hesitate if you have any question

thanks

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.