![2x^2+11x = 2 [ {(x+\dfrac{11}{4})^2-{(\dfrac{11}{4})}^2 ]](/tpl/images/0689/7298/4407e.png)
![h(x) = 2 [ {(x+\dfrac{11}{4})^2-{(\dfrac{11}{4})}^2 ] + 15\\= 2 {(x+\dfrac{11}{4})^2 +15-{\dfrac{11^2}{8}}\\= 2 {(x+\dfrac{11}{4})^2 +{\dfrac{15*8-11^2}{8}}](/tpl/images/0689/7298/e1655.png)
so
Rewrite the function by completing the square. h(x)=2x^2+11x+15
h(x)=__(x+__)^2+__...
Mathematics, 19.06.2020 04:57 tus
Rewrite the function by completing the square. h(x)=2x^2+11x+15
h(x)=__(x+__)^2+__
Answers: 2
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