Suppose a researcher is estimating the proportion of trees showing signs of disease in a local forest. They randomly sample 150 trees and find that 25 of them show signs of disease. Calculate the 95% confidence interval for p, the proportion of all trees in the forest showing signs of disease.

And the 95% confidence interval would be given (0.107;0.227).

Step-by-step explanation:

Information given

number of trees with signs of disease

the sample selected

the proportion of trees with signs of disease

The confidence interval for the true proportion would be given by this formula

For the 95% confidence interval the significance is and , and the critical value would be

And replacing we got:

And the 95% confidence interval would be given (0.107;0.227).

no this is a nonlinear negative

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step-by-step explanation: