The graph of f(x) is shown below. On a coordinate plane, a straight line has a negative slope and goes through (0, 6) and (3, 0). If f(x) and its inverse function, f Superscript negative 1 Baseline (x), are both plotted on the same coordinate plane, where is their point of intersection? (0,6) (1,4) (2,2) (3,0)

The intersection point is (2,2)

Step-by-step explanation:

First let's find the equation of f(x), using the linear model:

Using the point (0, 6), we have:

Using the point (3, 0), we have:

So we have that

To find f'(x) (the inverse of f(x)), we can substitute f(x) by x and x by f'(x) in the equation of f(x) and then isolate f'(x):

Now, to find the intersection point, we need to calculate f(x) = f'(x):

And the y-value is:

So the point is (2,2)