Plz help me 1. What was the theoretical probability of collecting a specific dinosaur, such as a Velociraptor, in a single purchase? 2. How many spins did it take before you had at least one of each dinosaur in Trial 1? Trial 2? Trial 3? 3. How does the number of spins correlate to the number of boxes of cereal that you would need to purchase? 4. What was the experimental probability for each dinosaur from Trial 1? Trial 2? Trial 3? 5. How does the experimental probability of getting each dinosaur differ from the theoretical probability? Here, you are comparing the experimental vs. theoretical probability of getting each type of dinosaur in a single purchase. In other words, you are determining the probability for a single event, not a compound event. 6.If someone bought eight boxes of cereal and got all eight dinosaurs, would you be surprised? Why or why not? 9. How did the experimental probabilities change between the trials? 8. What are the advantages of using a simulation versus actually buying boxes of cereal?

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

any of them that add up to 180 degrees.