If x = 39, y = 58, and the measure of AC = 4 units, what is the difference in length between segments AB and AD? Round your answer to the nearest hundredth.

1.64 units

Step-by-step explanation:

Given the following :

X = 39°

Y = 58°

AC = 4 units

Using triangle ABC with x = 39° and AC = 4UNITS,

USING THE Pythagoras, the SOHCAHTOA notation:

AC = opposite = 4units

AB = hypotenus

Sinθ = opposite / hypotenus

x = Θ = 39°

Sinx = opposite / hypotenus

Sin39° = 4 / AB

0.6293203 = 4 / AB

AB = (4  ÷ 0.6293203) = 6.3560629 units

Taking triangle ADC, with x = 58° and AC = 4UNITS,

AC = opposite = 4units

AD = hypotenus

Sinθ = opposite / hypotenus

y = Θ = 58°

Sinx = opposite / hypotenus

Sin58° = 4 / AD

0.8480480 = 4 / AD

AD = (4  ÷ 0.8480480) = 4.7167136 units

Difference between AB and AD

(6.3560629 - 4.7167136)  = 1.6393493

= 1.64 units

your answer would be 10x - 1

show us the graphs dude

step-by-step explanation: