. Assume the error in timing when starting and stopping the stopwatch is +0.2 seconds. So, if a single period is measured, the entire 0.2 second error affects this one period. Suppose the stopwatch is used to record 10 continuous periods, how much of this error affects a single period? How much for 50 continuous periods?

Im pretty sure it’s the first one

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60