Sue rolls a die twice. What is the probability as a fraction that she will get a three both times?

P =

Step-by-step explanation:

The probability of rolling a 3 on the first and second try is:

To get the probability of rolling a 3 both times is

The chance she rolls a 3 both times is

Step-by-step explanation: In this problem, we're given that a number cube is rolled twice and we're asked to find the probability or rolling a 3 and a 3.

It's important to understand that the two rolls of the number cube are independent events because the results of one role does not affect the results of the other roll. To find the probability of two independent events, we first find the probability of each event, then we multiply the probabilities.

So let's first find the probability of rolling a 6 with our first role of the number cube. Remember that we can find the probability of an event using the ratio number of favorable outcomes over total number of outcomes. Since there's only one way to roll a six and there are six possible outcomes 1 2 3 4 5 and 6, the probability of rolling a 6 is 1/6.

1/6 will also be the probability for the second role.

Now multiply 1/6 x 1/6 to get 1/36.

So, 1/36 is your answer.

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true