An army surplus store plans on making a tent with the dimensions shown. How much material is needed to make this tent? 15,200 square inches

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10,400 square inches

13,400 square inches

14,500 square inches

15,200in²

Step-by-step explanation:

The tent is shown in the attachment below.

Given=>

Triangular prism tent with the following dimensions:

base (h) = 60in

height of the triangle (h) = 40in

Length of the 3 sides of the triangle respectively (s1, s2, and s3) = 60in, 50in, 50in

Height of the prism (H) = 80in

==>REQUIRED:

Amount of material needed to make the tent = surface area of the triangular prism = bh + (s1 + s2 + s3)*H

==>SOLUTION:

Let us plug in our values using the formula for SA of a triangular prism.

Thus,

SA = 60*40 + (60 + 50 + 50)*80

SA = 2400 + (160)*80

SA = 2400 + 12,800

SA = 15,200in²

Material needed for the tent = 15,200 in²

no solution

step-by-step explanation:

there is not enough information in the problem to solve.