In a set of three lines, a pair of parallel lines is intersected by a transversal. The intersection forms eight special angles. Two of the special angles, A and B, are corresponding angles.

For the set of parallel lines intersected by a transversal, A = 4x and B = 2(x+14).

1. Use an equation to represent the corresponding angle relationship between A and B.

2. Use the equation to find the measures of A and B.

PLEASE HELP!!! Will mark brainliest and give thanks:)

∠A = ∠B = 56°

Step-by-step explanation:

When parallel lines are intersected by transversal, the corresponding angles are equal.

∠A = ∠B  

4x = 2(x+14)

4x = 2x + 2*14

4x = 2x + 28

4x - 2x = 28

2x = 28

x = 28/2

x = 14

∠A = 4x =  4 * 14 = 56°

∠B = 56

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph