Explain what is meant by the equation lim x → 8 f(x) = 9. If |x1 − 8| < |x2 − 8|, then |f(x1) − 9| < |f(x2) − 9|. The values of f(x) can be made as close to 8 as we like by taking x sufficiently close to 9. f(x) = 9 for all values of x. If |x1 − 8| < |x2 − 8|, then |f(x1) − 9|≤ |f(x2) − 9|. The values of f(x) can be made as close to 9 as we like by taking x sufficiently close to 8. Is it possible for this statement to be true and yet f(8) = 6? Explain. Yes, the graph could have a hole at (8, 9) and be defined such that f(8) = 6. Yes, the graph could have a vertical asymptote at x = 8 and be defined such that f(8) = 6. No, if f(8) = 6, then lim x→8 f(x) = 6. No, if lim x→8 f(x) = 9, then f(8) = 9.

Complete Question

1 Explain what is meant by the equation lim x → 8 f(x) = 9.

A If |x1 − 8| < |x2 − 8|, then |f(x1) − 9| < |f(x2) − 9|.

B The values of f(x) can be made as close to 8 as we like by taking x  sufficiently close to 9.

C  f(x) = 9 for all values of x.

D If |x1 − 8| < |x2 − 8|, then |f(x1) − 9|≤ |f(x2) − 9|.

E The values of f(x) can be made as close to 9 as we like by taking x sufficiently close to 8.

2  Is it possible for this statement to be true and yet f(8) = 6? Explain.

A Yes, the graph could have a hole at (8, 9) and be defined such that f(8) =6.

B Yes, the graph could have a vertical asymptote at x = 8 and be defined such that f(8) = 6.

C No, if f(8) = 6, then lim x→8 f(x) = 6.

D No, if lim x→8 f(x) = 9, then f(8) = 9.

1

   The correct option is  D

2

    The correct option is   A

Step-by-step explanation:

Generally a a limit function  

Tell us that as n tends toward x the values of  f(x) tends towards L hence for the first question E is the correct option

Now looking at the second question

  Yes it is possible for  lim x → 8 f(x) = 9.  to be true and  f(8) = 6 this is because the graph defined by this limit equation can have a hole the point

(8, 9) and created in such a way that f(8) = 6

the two may have that, even a breakdown is probably offered