Which of the points below does not lie on the curve y=x^2 ? (3/2, 9/2) (-1, 1) (4, 16) (1/2, 1/4)

We are given the equation y = x^2 and 4 points in the form (x, y).

Replace x and y in the equation with the values of x and y for each given point. The values that yield the same answer on both sides of the equation lie on the graph of y = x^2. The opposite is also true.

Let's try every point.

(3/2, 9/2)

9/2 = (3/2)^2

9/2 does not equal 9/4. Not a point on the graph of the equation.

1 = (-1)^2

1 = 1

Point on the graph of the equation.

(4, 16)

16 = 4^2

16 = 16

Point on the graph of the equation.

(1/2, 1/4)

1/4 = (1/2)^2

1/4 = 1/4

Point on the graph of the equation.

The only point not on the graph of the equation y = x^2 is (3/2, 9/2).

Understand?

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3