Find the center vertices and foci of the ellipse with equation 2x^3+8y^2=16

Step-by-step explanation:

First of all, you have a typo. But that's ok, we can work around it. The equation NOT yet in standard form for an ellipse should be:

Putting it into standard form requires that the right side of the equation equals 1. That means that we need to divide everything by 16 to accomplish that. When we do that, we will get the standard form:

The general form is either

or

where a is ALWAYS bigger than b. So if the bigger denominator is under the x numerator, this is an ellipse that is elongated horizontally. If the larger denominator is under the y numerator, then this is an ellipse that is elongated vertically. As you can see from our standard ellipse equation, the 8 is under the x numerator, so this is a horizontally elongated ellipse.

If then which is approximately 2.83 units.

If then which is approximately 1.41 units.

Since the ellipse is elongated horizontally, the a value starts at the center of the ellipse and goes 2.83 units to the right and left of the center; the b value starts at the center of the ellipse and goes 1.41 units both up and down from the center. But what's the center?

In the standard form above involving the h and the k in the numerators, the h and k indicate the coordinates of the center. h is like the x coordinate and k is like the y coordinate. Since our ellipse does not have a constant in a set of parenthesis for either the x or the y term, the center is at (0, 0). From the center then, we go go both right and left to (2.83, 0) and (-2.83, 0) for the vertices of the ellipse. The co-vertices would be (0, 1.41) and (0, -1.41).

The foci have the formula (h + c, k) for the focal point to the right of the center and (h - c, k) for the focal point to the left of the center. But how do we find c?

We already know that and so

and

That means that the foci have the coordinates and

and you're done!!

you have orange juice on wednesday. (idk why this is the answer)

step-by-step explanation:

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!