Color Blindness in Men and Women The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color blindness is much more common in men than in women (this is because the genes corresponding to the red and green receptors are located on the X-chromosome). Approximately of American men and of American women are red-green color-blind.1 Let and denote the events that a man or a woman is color-blind, respectively. A) If an Americal male is selected at random, what is the probability that he is red-green color-blind?
B) If an American female is selected at random, what is the probability that she is not red-green color-blind?
C) If one man and one woman are selected at random, what is the probability that neither are red-green color-blind?D) If one man and one woman are selected at random, what is the probability that at least one of them is red-green color-blind?

A. Probability the man is colorblind = 0.07

B. Probability the woman is not colorblind = 0.996

C. Probability neither the man or woman is colorblind = 0.926

D. Probability at least one of the woman or man is colorblind = 0.074

Note: The given question is missing some values. The question below is a sample question.

"The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color blindness is much more common in men than in women (this is because the genes corresponding to the red and green receptors are located on the X-chromosomes). Approximately 7% of American men and 0.4% of American women are red-green color-blind.

(a) If an American male is selected at random, what is the probability that he is red-green colorblind?

(b) If an American female is selected at random, what is the probability that she is NOT red-green color-blind?

(c) If one man and one woman are selected at random, what is the probability that neither are

red-green color-blind?

(d) If one man and one woman are selected at random, what is the probability that at least one of them is red-green color-blind?"

Step-by-Step Explanation:

Let cbM and cbW represent the events that a man or a woman is colorblind, respectively.

(a) 7% of men are colorblind, P(CBM) = 7/100 = 0.07.

(b) 0.4% of women are colorblind = 0.4/100 = 0.004

P(not cbW) = 1 - P(cbW)

P(not cbW) = 1 - 0.004 = 0.996.

(c) Probability the woman is not colorblind, P(not cbW) = 0.996,

Probability that the man is not color- blind, P(not cbM) = 1 - 0.07 = 0.93.

The two events are independent of each other, therefore, their probabilities are multiplied together:

P(neither is colorblind) = P(not cbM) × P(not cbW)

= 0.93 × 0.996 = 0.926.

(d) Probability that at least one is colorblind is the complement of the set P (neither is colorblind).

Therefore, P(at least one is colorblind) = 1 - P (Neither is Colorblind)

= 1 - 0.926 = 0.074

the answer is 48m^2!

step-by-step explanation:

d 600 because 15*10*2=300

300+300=600

step-by-step explanation: