At 5:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 38520 ft and is descending at the rate of 750 ft/min. Airplane #2 has an elevation of 9400 ft and is climbing at the rate of 550 ft/min. (1) Let t represent the time in minutes since 5:00 am, and let E represent the elevation in feet. Write an equation for the elevation of each plane in terms of t . plane #1: E ( t ) = plane #2: E ( t ) =

Plane 1

Plane 2

Step-by-step explanation:

As each plane is travelling at constant speed, each equation can be modelled after this expression:

Where:

- Intial elevation of the airplane, measured in feet.

- Climbing/Descending rate of the airplane, measured in feet per minute. (Positive - Climbing, Negative - Descending)

- Time, measured in minutes.

Equations are described below:

Plane 1

Plane 2

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)