Two scientists are measuring the temperature of liquids in two beakers. Liquid A has a temperature of -105.4° C and Liquid B has a temperature of -10.83 ° C. Which liquid is warmer and why?

Liquid B is warmer.

Step-by-step explanation:

The data that we have is:

Temperature A = -105.4° C

Temperature B = -10.83° C

We want to know which liquid is warmer, this is equivalent to see which temperature is bigger, Ta or Tb.

Now, you can see that temperature A is larger in module, but this is a negative number.

When we work with negative numbers, the bigger ones are the ones closer to zero. This means that for example, -1 is larger than - 150.

From this, we can conclude that Liquid B is warmer.

Another way to see it is with a change of units.

If we have A degrees Celcius, and we want to to transform it into Kelvins, we must add 273.15°.

Then we have:

Ta = (-105.4° + 273.15°) K = 167.75 K

Tb = (-10.83 ´273.15°) = 262.35 K

where you can see that liquid B has a larger temperature.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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step-by-step explanation: