Solve for x. |4x - 5| > 7

see explanation

Step-by-step explanation:

Inequalities of the type | x | > a have solutions in the form

x < - a OR x > a thus

4x - 5 < - 7 ( add 5 to both sides )

4x < - 2 ( divide both sides by 4 )

x < -

OR

4x - 5 > 7 ( add 5 to both sides )

4x > 12 ( divide both sides by 4 )

x > 3

Solution is x < - or x > 3

This can be expressed in interval notation as

(- ∞, - ) u (3, ∞ )

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a