In a class 28 of students, 9 have a cat and 8 have a dog. There are 6 students who have a cat and a dog. What is the probability that a student has a dog given that they do not have a cat?

Step-by-step explanation:

8 have a dog, and there are 28 students.

Simplify.

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.