Find the equation of the line through the point (6, -1) that is perpendicular to the line with equation y =1/2x-12

y + 1 = -2/1 (x - 6)

Step-by-step explanation:

The above equation is written in point slope from. To find the slope of a line perpendicular to another line all you have to do is find the opposite reciprocal to the slope of the original line. The original line's slope is 1/2, the reciprocal is 2/1 and to create the opposite reciprocal you have to change the sign of the slope, so the new slope is -2/1. To finish the rest of the equation you plug in the points given to you in the question.

Step-by-step explanation:

First, since the line is perpendicular to the given one, the slopes are negative reciprocals. The slope of the equation we must write is -2.

Now, we can set up point slope form:

y-y1 = m(x-x1)

y + 1 = -2(x - 6)

Now, we can change that to slope intercept form:

y + 1 = -2(x - 6)

y + 1 = -2x + 12

y = -2x -11

Hope this helped :)

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2