Use long division to find the quotient below. (12x3 + 3x2 - 108) = (3x-6)
O A. 4x2 + 6x + 18
O B. 4x2 + 9x + 18
O C. 4x2 - 6x + 18
D. 4x2-9x+18

B

Step-by-step explanation:

12x^3+3x^2-108 = 3x-6

3(4x^3+x^2-36) =3(x-2) ( divide by 3 both sides)

4x^3+x^2-36=x-2

4x^3+x^2-36

4x^3+x^2-36/x-2 =

divisor  4x^2           :(4x^2) (x-2) =4x^3-8x^2

                                 4x^3+x^2-36-4x^-8x^2 =9x^2-36

then divisor is 9x  :      9x(x-2)= 9x^2-18x

the remainder is :          9x^2-18x-9x^2-36 = 18x-36

then divisor is  18:              18(x-2) = 18x-36

subtract : 18x-36-(18x-36)= 0

the answer is 4x^2+9x+18

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

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