Ben uses a compass and a straightedge to construct ∠DEF ≅ ∠ABC, as shown below: The art shows two figures. The figure on the left shows two rays BA and BC having a common end point B. An arc drawn from B cut Which statement best explains why Ben uses the width BI to create the arc JK from point E? (6 points) A. ∠DEF ≅ ∠ABC when BH = EK, BI = JK, and HI = EJ. B. BI = JK when ∠DEF ≅ ∠ABC . C. BI = EJ when ∠DEF ≅ ∠ABC. D. ∠DEF ≅ ∠ABC when BH = EJ, BI = EK, and HI = JK.

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when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

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