Which function increases at the fastest rate between x = 0 and x = 8? A 2-column table with 5 rows titled Linear Function with the equation f of x = 2 x + 2. The first column is labeled x with entries 0, 2, 4, 6, 8. The second column is labeled f of x with entries 2, 6, 10, 14, 18.
A 2-column table with 5 rows titled Exponential Function with the equation f of x = 2 Superscript x Baseline + 2. The first column is labeled x with entries 0, 2, 4, 6, 8. The second column is labeled f of x with entries 3, 6, 18, 66, 258.
A 2-column table with 5 rows titled Quadratic Function with the equation f of x = 2 x squared + 2. The first column is labeled x with entries 0, 2, 4, 6, 8. The second column is labeled f of x with entries 2, 10, 34, 74, 130.
A 2-column table with 5 rows titled Linear Function with the equation f of x = 3 x + 2. The first column is labeled x with entries 0, 2, 4, 6, 8. The second column is labeled f of x with entries 2, 8, 14, 20, 26.

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4

the answer is:

mean: 6

mad: 2.14

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.