Calculate the perimeter of ABCD

28.13 cm

Step-by-step explanation:

The first step we need to do is create the segment AC.

Then, we can find its length using the law of cosines in the triangle ABC:

b^2 = a^2 + c^2 - 2*a*c*cos(B)

b^2 = 8^2 + 6^2 - 2*8*6*cos(95)

b^2 = 64 + 36 - 96*(-0.0872)

b^2 = 108.37

b = 10.41 cm

Then, in the triangle ADC, we can use the Pythagoras' theorem to find the length of DC:

DC^2 + DA^2 = AC^2

DC^2 + 25 = 108.37

DC^2 = 83.37

DC = 9.13 cm

So the perimeter of ABCD is:

Perimeter = AB + BC + CD + DA

Perimeter = 6 + 8 + 9.13 + 5 = 28.13 cm

u bout ugly as   a mf

step-by-step explanation: lol