Overbooking flights is a common practice of most airlines. A particular airline, believing that 3% of passengers fail to show for flights, overbooks (sells more tickets than there are seats). Suppose that for a particular flight involving a jumbo-jet with 267 seats, the airline sells 278 tickets. Question 1. What is the expected number of ticket holders that will fail to show for the flight

The expected number of ticket holders that will fail to show for the flight is 8.34.

Step-by-step explanation:

For each passenger, there are only two possible outcomes. Either they fail to show up to the flight, or they do not. The probability of a passenger not showing up is independent of other passengers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

3% of passengers fail to show for flights

This means that

The airline sells 278 tickets

This means that

What is the expected number of ticket holders that will fail to show for the flight

The expected number of ticket holders that will fail to show for the flight is 8.34.

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

1 and 0

step-by-step explanation: