3. A metal fabricating plant currently has five major pieces under contract each with a deadline for completion. Let X be the number of pieces completed by their deadlines, and suppose it's PMF p(x) is given by x 0 1 2 3 4 5 p(x) .05 .1 .15 .25 .35 .1 (a) Find and plot the CDF of X. (b) Use the CDF to find the probability that between one and four pieces, inclusive, are completed by their deadline

a) The cumulative distribution function would be given by:

x         0         1       2        3      4      5

F(X)  0.05   0.15  0.30  0.55  0.9    1

b)

And replacing we got:

Step-by-step explanation:

For this case we have the following probability distribution function given:

x        0       1       2       3       4       5

P(X)  0.05  0.1  0.15  0.25  0.35  0.1

We satisfy the conditions in order to have a probability distribution:

1)

2)

Part a

The cumulative distribution function would be given by:

x         0         1       2        3      4      5

F(X)  0.05   0.15  0.30  0.55  0.9    1

Part b

For this case we want to find this probability:

And replacing we got:

40 is the final : )

answer is x<