The motion of a ship riding at anchor can be modeled by y=25-4 cos (pi/6)t, where y is the water depth in feet and t is the time in hours. Consider a day in which t=0 represents 12:00 midnight. At what time during that day will the water under the ship be the deepest and what time will it be shallowest? What will the water’s depth be at these times?

29 feet (deepest) at 6 am

              21 feet (shallowest) at Midnight & Noon

Step-by-step explanation:

y = -4 cos (π/6)t +25

Amplitude (A) = 4    

-A means it is a reflection over the x-axis (starts at minimum)

Period = 2π/B   →  Period = 12

Phase shift = C/B   →  Phase Shift = 0

Midline (D) = 25

Midline (D) ± Amplitude (A) = Max & Min

Max: 25 + 4 = 29

Min: 25 - 4 = 21

Change the coordinates of y = cos (x) as follows:

x-value: Add C then divide by By-value: Multiply by A then add D

Note that the equation shows: A = -4, B = π/6, C = 0, D = 25

Same length is comparing because it’s saying its the same and not different

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!