The graph of the function f(x) = (x − 3)(x + 1) is shown. On a coordinate plane, a parabola opens up. It goes through (negative 1, 0), has a vertex at (1, negative 4), and goes through (3, 0). Which describes all of the values for which the graph is positive and decreasing? all real values of x where x < −1 all real values of x where x < 1 all real values of x where 1 < x < 3 all real values of x where x > 3

Correct option: first one -> all real values of x where x < −1

Step-by-step explanation:

First we need to find the roots of the function f(x):

0 = (x - 3)(x + 1)

(x - 3) = 0 -> x = 3

(x + 1) = 0 -> x = -1

The roots of the function are x = 3 and x = -1.

The vertex is between the roots (x = 1) and has a negative value of y (y = -4), so the concavity of the parabola is upwards.

So the graph is decreasing until it reaches the vertex, then the graph is increasing.

Then, we can affirm that the graph is positive and decreasing for all real values of x where x < -1 (for x > -1 and x < 3 we have negative values)

Correct option: first one

$35.59 in pounds

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b